Re: sql

am Fri, dem 02.02.2007, um 13:09:09 +0530 mailte Shyju Narayanan folgendes:
> Hi All
>
>
> BUT I NEED THE RESULT AS
> entry_user_id_int COUNT(VC) COUNT(VE) COUNT(CV) COUNT(SC) TOTAL
> 78 1 1 8 1 11
>

You need something like this (i called the table foo and without the
sc-column):

select entry_user_id_int,
sum(case when category_id_chv = 'VC' then 1 else 0 end) as "count(vc)",
sum(case when category_id_chv = 'VE' then 1 else 0 end),
sum(case when category_id_chv = 'CV' then 1 else 0 end),
sum(1)
from foo
where entry_user_id_int = 78
group by entry_user_id_int;
entry_user_id_int | count(vc) | sum | sum | sum
-------------------+-----------+-----+-----+-----
78 | 1 | 1 | 8 | 11

Andreas
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Andreas Kretschmer
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