From: | James William Pye <pgsql(at)jwp(dot)name> |
---|---|
To: | Andreas Erber <post(at)andreas-erber(dot)net> |
Cc: | pgsql-bugs(at)postgresql(dot)org |
Subject: | Re: BUG #2240: length() with geometric types |
Date: | 2006-02-07 01:22:51 |
Message-ID: | 20060207012251.GA26495@lit.jwp.name |
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Lists: | pgsql-bugs |
On Mon, Feb 06, 2006 at 02:41:39PM +0000, Andreas Erber wrote:
> Hi,
>
> I discovered some strange behaviour:
> The length() function returns different results depending on the geometric
> data type used as argument.
>
> length(lseg) produces the correct result, i.e. length(lseg('(0,0),(2,0)')) =
> 2
>
> length(path) always produces the double result (independently from the
> length of the path), i.e.
> length(path('(0,0),(2,0)')) = 4
> length(path('(0,0),(2,0),(4,0),(6,0),(8,0)')) = 16
>
> Is it supposed to be that way? If yes, why?
Yes.
You specified your path as a closed path. With its "loopback", it's twice as
long.
To specify it as an open path, do path('[(0,0),(2,0)]').
SELECT length(path('[(1,0),(0,0)]')) = '1';
SELECT length(path('(1,0),(0,0)')) = '2';
--
Regards, James William Pye
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