From: | Bruno Wolff III <bruno(at)wolff(dot)to> |
---|---|
To: | lucas(at)presserv(dot)org |
Cc: | pgsql-sql(at)postgresql(dot)org |
Subject: | Re: Sum() rows |
Date: | 2005-05-31 17:17:08 |
Message-ID: | 20050531171708.GB5899@wolff.to |
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Thread: | |
Lists: | pgsql-sql |
On Tue, May 31, 2005 at 13:36:48 -0300,
lucas(at)presserv(dot)org wrote:
> Hi.
> How can I sum a row and show the sum for each row???
Since in your example the id field gives the ordering, you can use a subselect
to add up the subtotal for rows with and id less than or equal to the value
of id for the current row.
> For example, in a finances table that have the total movimentation(debit/credit)
> in the bank.
>
> i.e:
> CREATE TABLE TB1 (id integer primary key, value numeric);
> insert into tb1 values (1,20);
> insert into tb1 values (2,2);
> insert into tb1 values (3,3);
> insert into tb1 values (4,17);
> insert into tb1 values (5,-0.5);
> insert into tb1 values (6,3);
>
> I want a query that returns:
> -id- | --- value --- | --- subtot ---
> 1 | 20.00 | 20.00
> 2 | 2.00 | 22.00
> 3 | 3.00 | 25.00
> 4 | 17.00 | 42.00
> 5 | -0.50 | 41.50
> 6 | 3.00 | 44.50
>
> The subtot colum will be the "prev. subtot colum"+"value colum". :-/
> I dont know how to make the "subtot" colum, I tried to use the sum() function
> but it not works correctly.
> Any idea???
>
> Thanks.
>
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