Re: A SQL Question About distinct, limit, group by, having, aggregate

Actually, i have a method to solve this problem.
But i really want to know, we have to write more statement to do one thing?

First step, we have to create 2 sequence. Let call them "foo" and "foo1".

create sequence foo;
create sequence foo1;

then, you can run below statement, and you will see the result that is we want.

select setval('foo',1);
select setval('foo1',1);
select id, score, class from (

select id, score, ph1.class , sequence1, sequence2, CASE WHEN ph1.cc > 5
THEN ph3.sequence + 4
ELSE ph3.sequence + ph1.cc - 1 END as tail from

(select class, count(*) as cc from allscore group by class)

as ph1 join

(select id, class, score, nextval('foo') as sequence1, currval('foo') as
sequence2 from (select * from allscore order by class, score desc) as t2)

as ph2 on (ph1.class = ph2.class) join

(select distinct on (class) class, nextval('foo1'), currval('foo1') as
sequence from (
select id , score , class from allscore order by class, score desc) as t6)

as ph3 on (ph2.class = ph3.class) order by ph1.class , score desc

) as con where sequence2 <= tail;

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