| From: | Bruno Wolff III <bruno(at)wolff(dot)to> |
|---|---|
| To: | Neil Dugan <postgres(at)butterflystitches(dot)com(dot)au> |
| Cc: | pgsql-general(at)postgresql(dot)org |
| Subject: | Re: find next in an index |
| Date: | 2005-02-13 03:47:39 |
| Message-ID: | 20050213034739.GB10271@wolff.to |
| Views: | Whole Thread | Raw Message | Download mbox | Resend email |
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| Lists: | pgsql-general |
On Sun, Feb 13, 2005 at 14:03:02 +1100,
Neil Dugan <postgres(at)butterflystitches(dot)com(dot)au> wrote:
> Hi,
> I am trying to find out how to get the next record according to a
> particular index.
> I have a table with a name field and a serial field. The name field
> isn't unique so I made an index on name(varchar) & serialno(bigserial).
> I also have an index just on 'name'. I am having trouble working out
> the syntax for the query.
>
> select * from table where name>='jack' and serialno!='2'
> order by name,serialno;
>
> I don't think this will work under all circumstances.
>
> Any help appreciated. Thanks.
I think using OFFSET 1 and LIMIT 2 with an appropiate WHERE clause
will get you want you want. If you are going to keep stepping through
the list, you might want to use a cursor.
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