From: | Martin Marques <martin(at)bugs(dot)unl(dot)edu(dot)ar> |
---|---|
To: | Tom Lane <tgl(at)sss(dot)pgh(dot)pa(dot)us>, Robert Creager <Robert_Creager(at)LogicalChaos(dot)org> |
Cc: | pgsql-sql(at)postgresql(dot)org |
Subject: | Re: inverse of "day of year" |
Date: | 2004-03-22 11:32:32 |
Message-ID: | 200403220832.32968.martin@bugs.unl.edu.ar |
Views: | Raw Message | Whole Thread | Download mbox | Resend email |
Thread: | |
Lists: | pgsql-sql |
El Vie 19 Mar 2004 12:10, Tom Lane escribió:
> Robert Creager <Robert_Creager(at)LogicalChaos(dot)org> writes:
> > Martin Marques <martin(at)bugs(dot)unl(dot)edu(dot)ar> confessed:
> >> Is there a function that would give me the date for a given day of year?
> >
> > Something like:
> >
> > select date_trunc( 'year', now() ) + (extract( doy from now() ) - 1) *
> > '1day'::interval;
>
> timestamp + interval arithmetic is likely to give you problems at
> daylight savings boundaries, since '1day' will be taken as '24hours'.
Is there information on how other intervals are taken? I mean, how is '1 year'
afected with the leap years?
--
08:30:01 up 13 days, 13:01, 3 users, load average: 2.04, 1.80, 1.04
-----------------------------------------------------------------
Martín Marqués | select 'mmarques' || '@' || 'unl.edu.ar'
Centro de Telematica | DBA, Programador, Administrador
Universidad Nacional
del Litoral
-----------------------------------------------------------------
From | Date | Subject | |
---|---|---|---|
Next Message | Achilleus Mantzios | 2004-03-22 11:40:11 | Re: special integrity constraints |
Previous Message | Bruno Wolff III | 2004-03-22 11:26:04 | Re: special integrity constraints |