From: | Michael A Nachbaur <mike(at)nachbaur(dot)com> |
---|---|
To: | "Ali Adams" <aliadams(at)doit4u(dot)com>, <pgsql-sql(at)postgresql(dot)org> |
Subject: | Re: help yourself by helping others |
Date: | 2003-07-10 20:00:43 |
Message-ID: | 200307101300.43414.mike@nachbaur.com |
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Lists: | pgsql-sql |
On Friday 04 April 2003 03:10 am, Ali Adams wrote:
> Dear All,
>
> I am new to Relational Databases and SQL and my background in ODBs is
> clouding my way to solving what seems to be a simple problem. I am sure
> many of you have met it many times.
<snip>
Assuming you can have multiple records per day per machine (e.g. you're
polling for information throughout the day), the following holds. However,
the output doesn't provide for a separate column per day, but rather you get
a separate row for each day/machine combination.
Attached is a file that demonstrates the behavior I think you would like. But
basically, here is the SQL statement you're looking for:
SELECT Datestamp, Machine, SUM(Withdrawls)
FROM WithdrawlsTable
GROUP BY Machine, Datestamp
ORDER BY Datestamp, Machine;
--
/* Michael A. Nachbaur <mike(at)nachbaur(dot)com>
* http://nachbaur.com/pgpkey.asc
*/
"A thought seemed to strike the woman. It struck her very slowly. You could
watch it coming in like a long wave on a sandy beach."
Attachment | Content-Type | Size |
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pgsql-example.sql | text/x-sql | 2.0 KB |
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