Re: SQL syntax

On Tue, 6 Aug 2002, frederic massot wrote:

> And I try to obtain for one month given (for example August : 8) two
> previous months, the current month, and nine next months :
>
>
> id_mois|mois_fr |mois_en |mois_de
> -------+---------+---------+---------
> 6|Juin |June |Juni
> 7|Juillet |July |Juli
> 8|Aout |August |August
> 9|Septembre|September|September
> 10|Octobre |October |Oktober
> 11|Novembre |November |November
> 12|Decembre |December |Dezember
> 1|Janvier |January |Januar
> 2|Fevrier |February |Februar
> 3|Mars |March |Marz
> 4|Avril |April |April
> 5|Mai |May |Aber
>
> Do you see how making in a SQL request ?

given m = 8:

select * from mois
order by case when id_mois < (m + 10) % 12 then id_mois + 13 else id_mois
end;

--
Tod McQuillin