From: | Bruce Momjian <pgman(at)candle(dot)pha(dot)pa(dot)us> |
---|---|
To: | Peter Eisentraut <peter_e(at)gmx(dot)net> |
Cc: | Michael Loftis <mloftis(at)wgops(dot)com>, PostgreSQL Development <pgsql-hackers(at)postgresql(dot)org> |
Subject: | Re: timeout implementation issues |
Date: | 2002-04-09 18:21:23 |
Message-ID: | 200204091821.g39ILNO27184@candle.pha.pa.us |
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Lists: | pgsql-hackers |
Peter Eisentraut wrote:
> Michael Loftis writes:
>
> > I was under the impression that for a transaction either all commands
> > succeed or all commands fail, atleast according to everything I've ever
> > read.
>
> That's an urban legend.
>
> A transaction guarantees (among other things) that all modifications to
> the database with the transaction are done atomicly (either all or done or
> none). This does not extend to the commands that supposedly initiate such
> modifications.
>
> Take out a database other than PostgreSQL and do
>
> BEGIN; -- or whatever they use; might be implicit
> INSERT INTO existing_table ('legal value');
> barf;
> COMMIT;
>
> The INSERT will most likely succeed. The reason is that "barf" does not
> modify or access the data in the database, so it does not affect the
> transactional integrity of the database.
Ewe, we do fail that test.
> We are trying to make the same argument for SET. SET does not modify the
> database, so it doesn't have to fall under transaction control.
OK, we have three possibilities:
o All SETs are honored in an aborted transaction
o No SETs are honored in an aborted transaction
o Some SETs are honored in an aborted transaction (current)
I think the problem is our current behavior. I don't think anyone can
say our it is correct (only honor SET before the transaction reaches
abort state). Whether we want the first or second is the issue, I think.
--
Bruce Momjian | http://candle.pha.pa.us
pgman(at)candle(dot)pha(dot)pa(dot)us | (610) 853-3000
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