Re: challenging query

>
> Consider the following table:
>
> A B C D select?
> -------------------------------
> 1 FOO A1 100 n
> 1 BAR Z2 100 n
> 2 FOO A1 101 y
> 2 BAR Z2 101 y
> 3 FOO A1 102 y
> 4 BAR Z2 99 y
> 5 FOO A1 99 n
> 6 BAR Z2 98 n
> 7 FOO AB 103 y
> 7 BAR ZY 103 y
>
> This table has the idea of "groups", that is, a group is defined as
> all of the words from B that have the same number A. The values in
> column C also matter- we want to select both groups A=7 and A=1 since
> they contain different values C. Note that the groups defined by A=1
> and A=3 are distinct- they do not contain the same number of words
> from B, so we want to select them both. Also note that D is datetime,
> and all the rows with the same number A will have the same D (this is
> actually ensured by a single row in another table.)
>
> I want to select all of the numbers A which define distinct groups and
> have the highest datetime D. Is this possible in a SQL query?

Sorry, there is an inconsistency in your question, at least to me.
In the table's last column you say you want to select
A in (2,3,4,7)
but in the epilogue you say you want to select
A in (7,1,1,3)
What did I miss?
Regards, Christoph