From: | Bruce Momjian <pgman(at)candle(dot)pha(dot)pa(dot)us> |
---|---|
To: | Kenneth Been <kennethb(at)telocity(dot)com> |
Cc: | pgsql-patches(at)postgresql(dot)org |
Subject: | Re: rtree improvements |
Date: | 2001-09-29 03:42:55 |
Message-ID: | 200109290342.f8T3guB02849@candle.pha.pa.us |
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Thread: | |
Lists: | pgsql-patches |
Patch applied. Thanks.
> I have made three changes to the rtree code: one bug fix and
> two performance improvements. I put an explanation of the
> changes at
>
> http://cs1.cs.nyu.edu/been/postgres-rtree.html
>
> The performance improvements are quite significant.
>
> All the changes are in the file src/backend/access/rtree/rtree.c
>
> I was working with the 7.1.3 code.
>
> I'm including the diff output as an attachment.
>
> Ken
>
> diff -Naur postgresql-7.1.3.old/src/backend/access/rtree/rtree.c postgresql-7.1.3/src/backend/access/rtree/rtree.c
> --- postgresql-7.1.3.old/src/backend/access/rtree/rtree.c Wed Mar 21 22:59:16 2001
> +++ postgresql-7.1.3/src/backend/access/rtree/rtree.c Tue Sep 25 13:56:31 2001
> @@ -55,6 +55,14 @@
> Datum spl_rdatum;
> } SPLITVEC;
>
> +/* for sorting tuples by cost, for picking split */
> +typedef struct SPLITCOST
> +{
> + OffsetNumber offset_number;
> + float cost_differential;
> + bool choose_left;
> +} SPLITCOST;
> +
> typedef struct RTSTATE
> {
> FmgrInfo unionFn; /* union function */
> @@ -79,6 +87,7 @@
> RTSTATE *rtstate);
> static int nospace(Page p, IndexTuple it);
> static void initRtstate(RTSTATE *rtstate, Relation index);
> +static int qsort_comp_splitcost(const void *a, const void *b);
>
>
> Datum
> @@ -427,7 +436,12 @@
> FunctionCall2(&rtstate->sizeFn, datum,
> PointerGetDatum(&newd_size));
>
> - if (newd_size != old_size)
> + /*
> + * If newd_size == 0 we have degenerate rectangles, so we
> + * don't know if there was any change, so we have to
> + * assume there was.
> + */
> + if ((newd_size == 0) || (newd_size != old_size))
> {
> TupleDesc td = RelationGetDescr(r);
>
> @@ -503,6 +517,8 @@
> OffsetNumber *spl_left,
> *spl_right;
> TupleDesc tupDesc;
> + int n;
> + OffsetNumber newitemoff;
>
> p = (Page) BufferGetPage(buffer);
> opaque = (RTreePageOpaque) PageGetSpecialPointer(p);
> @@ -539,56 +555,64 @@
> spl_right = v.spl_right;
> leftoff = rightoff = FirstOffsetNumber;
> maxoff = PageGetMaxOffsetNumber(p);
> - for (i = FirstOffsetNumber; i <= maxoff; i = OffsetNumberNext(i))
> - {
> - itemid = PageGetItemId(p, i);
> - item = (IndexTuple) PageGetItem(p, itemid);
> -
> - if (i == *spl_left)
> - {
> - if (PageAddItem(left, (Item) item, IndexTupleSize(item),
> - leftoff, LP_USED) == InvalidOffsetNumber)
> - elog(ERROR, "rtdosplit: failed to copy index item in %s",
> - RelationGetRelationName(r));
> - leftoff = OffsetNumberNext(leftoff);
> - spl_left++; /* advance in left split vector */
> - }
> - else
> - {
> - Assert(i == *spl_right);
> - if (PageAddItem(right, (Item) item, IndexTupleSize(item),
> - rightoff, LP_USED) == InvalidOffsetNumber)
> - elog(ERROR, "rtdosplit: failed to copy index item in %s",
> - RelationGetRelationName(r));
> - rightoff = OffsetNumberNext(rightoff);
> - spl_right++; /* advance in right split vector */
> - }
> - }
> + newitemoff = OffsetNumberNext(maxoff);
>
> /* build an InsertIndexResult for this insertion */
> res = (InsertIndexResult) palloc(sizeof(InsertIndexResultData));
>
> - /* now insert the new index tuple */
> - if (*spl_left == maxoff + 1)
> + /*
> + * spl_left contains a list of the offset numbers of the
> + * tuples that will go to the left page. For each offset
> + * number, get the tuple item, then add the item to the
> + * left page. Similarly for the right side.
> + */
> +
> + /* fill left node */
> + for (n = 0; n < v.spl_nleft; n++)
> {
> - if (PageAddItem(left, (Item) itup, IndexTupleSize(itup),
> + i = *spl_left;
> + if (i == newitemoff)
> + item = itup;
> + else
> + {
> + itemid = PageGetItemId(p, i);
> + item = (IndexTuple) PageGetItem(p, itemid);
> + }
> +
> + if (PageAddItem(left, (Item) item, IndexTupleSize(item),
> leftoff, LP_USED) == InvalidOffsetNumber)
> elog(ERROR, "rtdosplit: failed to add index item to %s",
> RelationGetRelationName(r));
> leftoff = OffsetNumberNext(leftoff);
> - ItemPointerSet(&(res->pointerData), lbknum, leftoff);
> - spl_left++;
> +
> + if (i == newitemoff)
> + ItemPointerSet(&(res->pointerData), lbknum, leftoff);
> +
> + spl_left++; /* advance in left split vector */
> }
> - else
> +
> + /* fill right node */
> + for (n = 0; n < v.spl_nright; n++)
> {
> - Assert(*spl_right == maxoff + 1);
> - if (PageAddItem(right, (Item) itup, IndexTupleSize(itup),
> + i = *spl_right;
> + if (i == newitemoff)
> + item = itup;
> + else
> + {
> + itemid = PageGetItemId(p, i);
> + item = (IndexTuple) PageGetItem(p, itemid);
> + }
> +
> + if (PageAddItem(right, (Item) item, IndexTupleSize(item),
> rightoff, LP_USED) == InvalidOffsetNumber)
> elog(ERROR, "rtdosplit: failed to add index item to %s",
> RelationGetRelationName(r));
> rightoff = OffsetNumberNext(rightoff);
> - ItemPointerSet(&(res->pointerData), rbknum, rightoff);
> - spl_right++;
> +
> + if (i == newitemoff)
> + ItemPointerSet(&(res->pointerData), rbknum, rightoff);
> +
> + spl_right++; /* advance in right split vector */
> }
>
> /* Make sure we consumed all of the split vectors, and release 'em */
> @@ -741,8 +765,10 @@
> * In addition, the item to be added (itup) is listed in the appropriate
> * vector. It is represented by item number N+1 (N = # of items on page).
> *
> - * Both vectors appear in sequence order with a terminating sentinel value
> - * of InvalidOffsetNumber.
> + * Both vectors have a terminating sentinel value of InvalidOffsetNumber,
> + * but the sentinal value is no longer used, because the SPLITVEC
> + * vector also contains the length of each vector, and that information
> + * is now used to iterate over them in rtdosplit(). --kbb, 21 Sept 2001
> *
> * The bounding-box datums for the two new pages are also returned in *v.
> *
> @@ -797,6 +823,12 @@
> item_2_sz,
> left_avail_space,
> right_avail_space;
> + int total_num_tuples,
> + num_tuples_without_seeds,
> + max_after_split; /* in Guttman's lingo, (M - m) */
> + float diff; /* diff between cost of putting tuple left or right */
> + SPLITCOST *cost_vector;
> + int n;
>
> /*
> * First, make sure the new item is not so large that we can't
> @@ -812,6 +844,9 @@
> maxoff = PageGetMaxOffsetNumber(page);
> newitemoff = OffsetNumberNext(maxoff); /* phony index for new
> * item */
> + total_num_tuples = newitemoff;
> + num_tuples_without_seeds = total_num_tuples - 2;
> + max_after_split = total_num_tuples / 2; /* works for m = M/2 */
>
> /* Make arrays big enough for worst case, including sentinel */
> nbytes = (maxoff + 2) * sizeof(OffsetNumber);
> @@ -909,47 +944,111 @@
> right_avail_space = RTPageAvailSpace - IndexTupleTotalSize(item_2);
>
> /*
> - * Now split up the regions between the two seeds. An important
> - * property of this split algorithm is that the split vector v has the
> - * indices of items to be split in order in its left and right
> - * vectors. We exploit this property by doing a merge in the code
> - * that actually splits the page.
> + * Now split up the regions between the two seeds.
> + *
> + * The cost_vector array will contain hints for determining where
> + * each tuple should go. Each record in the array will contain
> + * a boolean, choose_left, that indicates which node the tuple
> + * prefers to be on, and the absolute difference in cost between
> + * putting the tuple in its favored node and in the other node.
> *
> - * For efficiency, we also place the new index tuple in this loop. This
> - * is handled at the very end, when we have placed all the existing
> - * tuples and i == maxoff + 1.
> + * Later, we will sort the cost_vector in descending order by cost
> + * difference, and consider the tuples in that order for
> + * placement. That way, the tuples that *really* want to be in
> + * one node or the other get to choose first, and the tuples that
> + * don't really care choose last.
> + *
> + * First, build the cost_vector array. The new index tuple will
> + * also be handled in this loop, and represented in the array,
> + * with i==newitemoff.
> + *
> + * In the case of variable size tuples it is possible that we only
> + * have the two seeds and no other tuples, in which case we don't
> + * do any of this cost_vector stuff.
> */
> +
> + /* to keep compiler quiet */
> + cost_vector = (SPLITCOST *) NULL;
> +
> + if (num_tuples_without_seeds > 0)
> + {
> + cost_vector =
> + (SPLITCOST *) palloc(num_tuples_without_seeds * sizeof(SPLITCOST));
> + n = 0;
> + for (i = FirstOffsetNumber; i <= newitemoff; i = OffsetNumberNext(i))
> + {
> + /* Compute new union datums and sizes for both choices */
> +
> + if ((i == seed_1) || (i == seed_2))
> + continue;
> + else if (i == newitemoff)
> + item_1 = itup;
> + else
> + item_1 = (IndexTuple) PageGetItem(page, PageGetItemId(page, i));
> +
> + datum_alpha = IndexTupleGetDatum(item_1);
> + union_dl = FunctionCall2(&rtstate->unionFn, datum_l, datum_alpha);
> + union_dr = FunctionCall2(&rtstate->unionFn, datum_r, datum_alpha);
> + FunctionCall2(&rtstate->sizeFn, union_dl,
> + PointerGetDatum(&size_alpha));
> + FunctionCall2(&rtstate->sizeFn, union_dr,
> + PointerGetDatum(&size_beta));
> +
> + diff = (size_alpha - size_l) - (size_beta - size_r);
> +
> + cost_vector[n].offset_number = i;
> + cost_vector[n].cost_differential = fabs(diff);
> + cost_vector[n].choose_left = (diff < 0);
> +
> + n++;
> + }
> +
> + /*
> + * Sort the array. The function qsort_comp_splitcost is
> + * set up "backwards", to provided descending order.
> + */
> + qsort(cost_vector, num_tuples_without_seeds, sizeof(SPLITCOST),
> + &qsort_comp_splitcost);
> + }
> +
> + /*
> + * Now make the final decisions about where each tuple will go,
> + * and build the vectors to return in the SPLITVEC record.
> + *
> + * The cost_vector array contains (descriptions of) all the
> + * tuples, in the order that we want to consider them, so we
> + * we just iterate through it and place each tuple in left
> + * or right nodes, according to the criteria described below.
> + */
> +
> left = v->spl_left;
> v->spl_nleft = 0;
> right = v->spl_right;
> v->spl_nright = 0;
>
> - for (i = FirstOffsetNumber; i <= newitemoff; i = OffsetNumberNext(i))
> + /* Place the seeds first.
> + * left avail space, left union, right avail space, and right
> + * union have already been adjusted for the seeds.
> + */
> +
> + *left++ = seed_1;
> + v->spl_nleft++;
> +
> + *right++ = seed_2;
> + v->spl_nright++;
> +
> + for (n = 0; n < num_tuples_without_seeds; n++)
> {
> bool left_feasible,
> right_feasible,
> choose_left;
>
> /*
> - * If we've already decided where to place this item, just put it
> - * on the correct list. Otherwise, we need to figure out which
> - * page needs the least enlargement in order to store the item.
> + * We need to figure out which page needs the least
> + * enlargement in order to store the item.
> */
>
> - if (i == seed_1)
> - {
> - *left++ = i;
> - v->spl_nleft++;
> - /* left avail_space & union already includes this one */
> - continue;
> - }
> - if (i == seed_2)
> - {
> - *right++ = i;
> - v->spl_nright++;
> - /* right avail_space & union already includes this one */
> - continue;
> - }
> + i = cost_vector[n].offset_number;
>
> /* Compute new union datums and sizes for both possible additions */
> if (i == newitemoff)
> @@ -979,6 +1078,24 @@
> * (We know that all the old items together can fit on one page, so
> * we need not worry about any other problem than failing to fit
> * the new item.)
> + *
> + * Guttman's algorithm actually has two factors to consider (in
> + * order): 1. if one node has so many tuples already assigned to
> + * it that the other needs all the rest in order to satisfy the
> + * condition that neither node has fewer than m tuples, then
> + * that is decisive; 2. otherwise, choose the page that shows
> + * the smaller enlargement of its union area.
> + *
> + * I have chosen m = M/2, where M is the maximum number of
> + * tuples on a page. (Actually, this is only strictly
> + * true for fixed size tuples. For variable size tuples,
> + * there still might have to be only one tuple on a page,
> + * if it is really big. But even with variable size
> + * tuples we still try to get m as close as possible to M/2.)
> + *
> + * The question of which page shows the smaller enlargement of
> + * its union area has already been answered, and the answer
> + * stored in the choose_left field of the SPLITCOST record.
> */
> left_feasible = (left_avail_space >= item_1_sz &&
> ((left_avail_space - item_1_sz) >= newitemsz ||
> @@ -988,8 +1105,18 @@
> left_avail_space >= newitemsz));
> if (left_feasible && right_feasible)
> {
> - /* Both feasible, use Guttman's algorithm */
> - choose_left = (size_alpha - size_l < size_beta - size_r);
> + /*
> + * Both feasible, use Guttman's algorithm.
> + * First check the m condition described above, and if
> + * that doesn't apply, choose the page with the smaller
> + * enlargement of its union area.
> + */
> + if (v->spl_nleft > max_after_split)
> + choose_left = false;
> + else if (v->spl_nright > max_after_split)
> + choose_left = true;
> + else
> + choose_left = cost_vector[n].choose_left;
> }
> else if (left_feasible)
> choose_left = true;
> @@ -1023,6 +1150,11 @@
> }
> }
>
> + if (num_tuples_without_seeds > 0)
> + {
> + pfree(cost_vector);
> + }
> +
> *left = *right = InvalidOffsetNumber; /* add ending sentinels */
>
> v->spl_ldatum = datum_l;
> @@ -1152,6 +1284,21 @@
> fmgr_info(size_proc, &rtstate->sizeFn);
> fmgr_info(inter_proc, &rtstate->interFn);
> return;
> +}
> +
> +/* for sorting SPLITCOST records in descending order */
> +static int
> +qsort_comp_splitcost(const void *a, const void *b)
> +{
> + float diff =
> + ((SPLITCOST *)a)->cost_differential -
> + ((SPLITCOST *)b)->cost_differential;
> + if (diff < 0)
> + return 1;
> + else if (diff > 0)
> + return -1;
> + else
> + return 0;
> }
>
> #ifdef RTDEBUG
>
> ---------------------------(end of broadcast)---------------------------
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>
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--
Bruce Momjian | http://candle.pha.pa.us
pgman(at)candle(dot)pha(dot)pa(dot)us | (610) 853-3000
+ If your life is a hard drive, | 830 Blythe Avenue
+ Christ can be your backup. | Drexel Hill, Pennsylvania 19026
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