From: | wsheldah(at)lexmark(dot)com |
---|---|
To: | "G(dot)L(dot) Grobe" <gary(at)grobe(dot)net> |
Cc: | pgsql-general(at)postgresql(dot)org |
Subject: | Re: query help |
Date: | 2001-08-31 12:41:48 |
Message-ID: | 200108311242.IAA23268@interlock2.lexmark.com |
Views: | Raw Message | Whole Thread | Download mbox | Resend email |
Thread: | |
Lists: | pgsql-general |
For one specific label:
select TableB.label from TableA, TableB where TableA.idA=TableB.idA and
TableA.name='test2';
To get a list of name-label pairs:
select TableA.name, TableB.label from TableA, TableB where TableA.idA=TableB.idA
order by TableA.name, TableB.label;
"G.L. Grobe" <gary%grobe(dot)net(at)interlock(dot)lexmark(dot)com> on 08/30/2001 07:45:20 PM
To: pgsql-general%postgresql(dot)org(at)interlock(dot)lexmark(dot)com
cc: (bcc: Wesley Sheldahl/Lex/Lexmark)
Subject: [GENERAL] query help
Hi all,
How would I get TableB.label if all I know about is TableA.name?
I was thinking about a query on TableA first, then within the while
(rs.next()), I'd do another query using the result set from A on B, but I
don't like that much, and it seems kind of slow.
Any help much appreciated!
TableA
idA | name | class
-----------------
11 test1 1
12 test2 1
13 test3 2
14 test4 2
TableB
idB | idA | label
----------------
1 11 nameA
2 12 nameB
3 13 nameC
4 14 nameD
---------------------------(end of broadcast)---------------------------
TIP 2: you can get off all lists at once with the unregister command
(send "unregister YourEmailAddressHere" to majordomo(at)postgresql(dot)org)
From | Date | Subject | |
---|---|---|---|
Next Message | Mike Arace | 2001-08-31 12:59:53 | Deployment of PostgreSQL Applications |
Previous Message | Arne Weiner | 2001-08-31 11:46:42 | Re: What's wrong about this sql statement? |