Using aggregate in HAVING

From: Bruce Momjian <pgman(at)candle(dot)pha(dot)pa(dot)us>
To: PostgreSQL-development <pgsql-hackers(at)postgreSQL(dot)org>
Subject: Using aggregate in HAVING
Date: 1999-12-29 19:51:19
Message-ID: 199912291951.OAA08646@candle.pha.pa.us
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How would I get all friends greater than the average age?

CREATE TABLE friends (
firstname CHAR(15),
lastname CHAR(20),
age INTEGER)

SELECT firstname, lastname
FROM friends
HAVING age >= AVG(age)

ERROR: Attribute friends.firstname must be GROUPed or used in an
aggregate function

This fails too:

SELECT firstname, lastname
FROM friends
WHERE age >= AVG(age)

ERROR: Aggregates not allowed in WHERE clause

This fails. I am stumped.

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