David Rowley <dgrowleyml(at)gmail(dot)com> writes:
> hmm ok. I imagine there must be a better way to say that then since
> it confused at least 1 reader so far. My problem is that I assumed
> "result" meant the result of the function that the comment is written
> in, not the result of evaluating the given expression during
> execution. If that was more clear then I'd not have been misled.
Maybe like
case T_ScalarArrayOpExpr:
/* ScalarArrayOpExpr's result is boolean ... */
coll = InvalidOid; /* ... so it has no collation */
break;
?
regards, tom lane