BUG #17957: psql-16beta1 \df+ does not show the function body

From: PG Bug reporting form <noreply(at)postgresql(dot)org>
To: pgsql-bugs(at)lists(dot)postgresql(dot)org
Cc: bzm(at)2bz(dot)de
Subject: BUG #17957: psql-16beta1 \df+ does not show the function body
Date: 2023-06-01 17:57:19
Message-ID: 17957-e1db8b1c15af444a@postgresql.org
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The following bug has been logged on the website:

Bug reference: 17957
Logged by: Boris Z
Email address: bzm(at)2bz(dot)de
PostgreSQL version: 16beta1
Operating system: OSX, Linux
Description:

Hi,

The release notes do not mention \df+.
https://www.postgresql.org/docs/16/release-16.html#RELEASE-16-PSQL

for testing I used this function, but any user function will do.

CREATE OR REPLACE FUNCTION test_function()
RETURNS bigint
AS $$
SELECT 1;
$$ LANGUAGE sql
STABLE
PARALLEL SAFE;

When using psql (16beta1)
=# \df+ test_function
-[ RECORD 1 ]-------+--------------
Schema | public
Name | test_function
Result data type | bigint
Argument data types |
Type | func
Volatility | stable
Parallel | safe
Owner | bz
Security | invoker
Access privileges |
Language | sql
Internal name |
Description |

using psql-15.3 it works as expected
=# \df+ test_function
-[ RECORD 1 ]-------+--------------
Schema | public
Name | test_function
Result data type | bigint
Argument data types |
Type | func
Volatility | stable
Parallel | safe
Owner | bz
Security | invoker
Access privileges |
Language | sql
Source code | +
| SELECT 1;+
|
Description |

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