From: | Alexander Lakhin <exclusion(at)gmail(dot)com> |
---|---|
To: | Tom Lane <tgl(at)sss(dot)pgh(dot)pa(dot)us> |
Cc: | pgsql-bugs(at)lists(dot)postgresql(dot)org |
Subject: | Re: BUG #16790: Integer overflow not detected with << |
Date: | 2020-12-23 17:50:00 |
Message-ID: | 17340682-ad3e-9145-543a-27a62518357e@gmail.com |
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Lists: | pgsql-bugs |
23.12.2020 18:29, Tom Lane wrote:
> PG Bug reporting form <noreply(at)postgresql(dot)org> writes:
>> It seems that the bitwise shift left operator ignores overflow:
>> Is this an expected behavior (a kind of UB)? It's not like an arithmetic
>> shift. (The semantic of '1::int4<<-1' is questionable too.)
> It's defined to do whatever the C << operator does. That will certainly
> not involve throwing an error.
Unfortunately, the behavior of the C << operator varies from defined to
implementation-defined and undefined. In fact I found this issue when
executing that query in an instance built with "-fsanitize=undefined".
Also I found an interesting reading about the shift operator:
https://devblogs.microsoft.com/cppblog/hello-arm-exploring-undefined-unspecified-and-implementation-defined-behavior-in-c/
So it's not that simple to describe the expected result of the operator
for all cases/platforms/architectures. It seems that a user is left with
"just try and see" or "avoid illegal values" approach.
On the other hand, there are pg_{mul,add,sub}_s{16,32,64}_overflow()
functions. Aren't they purposed to provide a well-defined behaviour for
related arithmetic operators?
Maybe the bitwise shift can be thought as something different from
arithmetic shift, and i<<1 is not the same as i*2, but in my opinion
it's not that could be expected at the database level.
Best regards,
Alexander
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