Re: 9.0b1: "ERROR: btree index keys must be ordered by attribute"

Ian Barwick <barwick(at)gmail(dot)com> writes:
> Apologies, slight c&p error; correct version of query:

> SELECT ov.object_id
> FROM object_version ov
> WHERE ov.object_id = 1
> AND ov.version =0
> AND ov.object_status_id = (
> SELECT MAX(ov1.object_status_id)
> FROM object_version ov1
> WHERE ov1.object_id=ov.object_id
> AND ov1.version = ov.version
> AND ov1.lang = ov.lang
> )
> AND ov.lang = 'en';

Ah, I see it:

-> Index Scan Backward using object_version_object_id_version_object_status_id_lang_key on object_version ov1 (cost=0.00..8.27 rows=1 width=4)
Index Cond: ((object_id = $0) AND (version = $1) AND (lang = $2) AND (object_status_id IS NOT NULL))

where

regression=# \d object_version_object_id_version_object_status_id_lang_key
Index "public.object_version_object_id_version_object_status_id_lang_key"
Column | Type | Definition
------------------+--------------+------------------
object_id | integer | object_id
version | integer | version
object_status_id | integer | object_status_id
lang | character(2) | lang
unique, btree, for table "public.object_version"

The index-based-max code is throwing in the IS NOT NULL condition
without thought for where it has to go in the index condition order.
Will look into fixing this tomorrow.

regards, tom lane