Re: BUG #5032: unexpected syntax error for plpgsql function returns table

From: Pavel Stehule <pavel(dot)stehule(at)gmail(dot)com>
To: Keith Cascio <keith(at)cs(dot)ucla(dot)edu>
Cc: pgsql-bugs(at)postgresql(dot)org
Subject: Re: BUG #5032: unexpected syntax error for plpgsql function returns table
Date: 2009-09-03 06:31:53
Message-ID: 162867790909022331g6f676e36x6dfe30445661e3cf@mail.gmail.com
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2009/9/3 Keith Cascio <keith(at)cs(dot)ucla(dot)edu>:
> Pavel,
>
> On Thu, 3 Sep 2009, Pavel Stehule wrote:
>
>> it's not bug - PostgreSQL doesn't support parameter placeholder on this
>> position. Use dynamic query instead - plpgsql statement EXECUTE.
>
> Thank you for your reply.  I appreciate your suggestion, but it still seems like
> a bug to me.  Please comment on the fact that the following code succeeds:
>
> create function reproduce() returns table(foo integer) language plpgsql as
> 'begin return query select 1 bar; end;';
>
> Output in psql is:
> CREATE FUNCTION
>
> Why should it succeed with "bar" but not with "foo"?

because bar isn't declared as variable

regards
Pavel
>
> Thanks,
> Keith
>
>
>> 2009/9/3 Keith Cascio <keith(at)cs(dot)ucla(dot)edu>:
>> > create function reproduce() returns table(foo integer) language plpgsql as
>> > 'begin return query select 1 foo; end;';
>

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