Re: Query problem

From: "Pavel Stehule" <pavel(dot)stehule(at)gmail(dot)com>
To: "Clemens Schwaighofer" <cs(at)tequila(dot)co(dot)jp>
Cc: pgsql-general(at)postgresql(dot)org
Subject: Re: Query problem
Date: 2007-10-12 14:22:32
Message-ID: 162867790710120722w3a4abc14s1bde65f18577eedc@mail.gmail.com
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2007/10/12, Clemens Schwaighofer <cs(at)tequila(dot)co(dot)jp>:
> hi,
>
> thats the first time I am a bit confused by a query not working.
>
> I have this table:
>
> gullevek=# \d test
> Table "public.test"
> Column | Type | Modifiers
> ---------+-------------------+--------------------------------------------------------
> test_id | integer | not null default
> nextval('test_test_id_seq'::regclass)
> email_a | character varying |
> email_b | character varying |
> Indexes:
> "test_pkey" PRIMARY KEY, btree (test_id)
>
> with this content:
>
> gullevek=# select * from test;
> test_id | email_a | email_b
> ---------+---------------+-------------
> 2 | test(at)test(dot)com | bar(at)foo(dot)com
> 1 | foo(at)bar(dot)com |
> (2 rows)
>
> if I do this select:
>
> select * from (select test_id, email_a FROM test WHERE email_a =
> 'moo(at)boo(dot)com') as s, (select test_id, email_b from test where email_b =
> 'bar(at)foo(dot)com') as t;
>

you get 0 rows. moo(at)boo(dot)com isn't anywhere and bar(at)foo(dot)com cannot do
pair with any. else 0 * 1 = 0

Pavel

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