From: | Tom Lane <tgl(at)sss(dot)pgh(dot)pa(dot)us> |
---|---|
To: | "Vance Maverick" <vmaverick(at)pgp(dot)com> |
Cc: | pgsql-general(at)postgresql(dot)org |
Subject: | Re: remove indexes on a column? |
Date: | 2008-09-10 04:23:36 |
Message-ID: | 15591.1221020616@sss.pgh.pa.us |
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Lists: | pgsql-general |
"Vance Maverick" <vmaverick(at)pgp(dot)com> writes:
> I'd like to write a SQL script, possibly with some PL/pgSQL, that can
> find all indexes on a column -- so I can remove them, and set up
> exactly the indexes I want.
Yeah, this seems a bit tricky if you have expression indexes involving
the column. I concur that trying to parse the expressions is a bad
idea --- even if your code works today, it'll probably break in future
PG releases, because the nodetree representation is not very stable.
What I'd look for is pg_depend entries showing indexes that depend on
the column. Here's a hint:
regression=# create table foo (f1 int);
CREATE TABLE
regression=# create index fooi on foo (abs(f1));
CREATE INDEX
regression=# select * from pg_depend where refobjid = 'foo'::regclass;
classid | objid | objsubid | refclassid | refobjid | refobjsubid | deptype
---------+--------+----------+------------+----------+-------------+---------
1247 | 534605 | 0 | 1259 | 534603 | 0 | i
1259 | 534606 | 0 | 1259 | 534603 | 1 | a
(2 rows)
regression=# select 534606::regclass;
regclass
----------
fooi
(1 row)
regards, tom lane
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