Re: Elegant SQL solution:

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> SELECT date_part('month',rowdate) as month, count(*) as rows FROM mytable GROUP
> BY month;
>...
> I could create a one-column table with values 1 - 12 in it, and select from
> that table with a where clause matching "month". I could also create a view
> "SELECT 1 UNION SELECT 2 UNION ..." and select against the view. There MUST be
> a more elegant way to do this.

The first solution is probably the best one. It does not seem that "unelegant"
to me. Another way would be just to do it in the application itself.

...or you could consider this one I came up with. Use at your own risk ;)

SELECT dos.mym AS "Month", COALESCE(uno.rc,0) AS "Total" FROM
(SELECT date_part('month',rowdate) AS mym, count(*) AS rc
FROM mytable GROUP BY 1) AS uno
RIGHT JOIN
(SELECT oid::integer-15 AS mym
FROM pg_type ORDER BY oid ASC LIMIT 12) AS dos
USING (mym);

- --
Greg Sabino Mullane greg(at)turnstep(dot)com
PGP Key: 0x14964AC8 200306072131

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