| From: | "Basques, Bob (CI-StPaul)" <bob(dot)basques(at)ci(dot)stpaul(dot)mn(dot)us> |
|---|---|
| To: | David Gauthier <davegauthierpg(at)gmail(dot)com> |
| Cc: | "pgsql-general(at)lists(dot)postgresql(dot)org" <pgsql-general(at)lists(dot)postgresql(dot)org> |
| Subject: | Re: How to reformat output of "age()" function |
| Date: | 2019-09-11 16:12:21 |
| Message-ID: | 1402ED33-C80E-43E0-AB2A-D29326CAD3A7@ci.stpaul.mn.us |
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| Lists: | pgsql-general |
SELECT EXTRACT(EPOCH FROM age('2019-09-11 09:00:00','2019-09-09 11:00:00')::INTERVAL)/60;
A nice explanation and even a slick function are here:
https://stackoverflow.com/questions/3460805/postgresql-format-interval-as-minutes
bobb
On Sep 11, 2019, at 10:38 AM, David Gauthier <davegauthierpg(at)gmail(dot)com<mailto:davegauthierpg(at)gmail(dot)com>> wrote:
How can I change the default output of the "age" function to be, for example, in minutes?
E.g.
dvdb=> select age('2019-09-11 09:00:00','2019-09-09 11:00:00');
age
----------------
1 day 22:00:00
(1 row)
I want the equivalent of that time delta in minutes.
Thanks in Advance
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