Re: possible bug on age() function (8.2.4 , 8.3.6)

Le mercredi 24 juin 2009 à 12:45 +0000, Jasen Betts a écrit :
> On 2009-06-24, Philippe Amelant <pamelant(at)companeo(dot)com> wrote:
> > Ok but if I work with hours or whatever the problem is still there
> >
> > SELECT (EXTRACT(EPOCH FROM TIMESTAMP '2009-06-23 18:36:05.064066+02') -
> > EXTRACT(EPOCH FROM TIMESTAMP '"2009-05-12 18:36:05.064066+02"'))/3600,
> > EXTRACT(EPOCH FROM interval '1008 hours')/3600, age('2009-06-23
> > 18:36:05.064066+02' ,'"2009-05-12 18:36:05.064066+02"') > interval '1007
> > hours';
> >
> > The third test should be true and not false
>
> The third test is comparing a double with an interval.
> compare like with like.
>
> SELECT (EXTRACT(EPOCH FROM TIMESTAMP '2009-06-23 18:36:05.064066+02') -
> EXTRACT(EPOCH FROM TIMESTAMP '"2009-05-12 18:36:05.064066+02"'))/3600,
> EXTRACT(EPOCH FROM interval '1008 hours')/3600, age('2009-06-23
> 18:36:05.064066+02' ,'"2009-05-12 18:36:05.064066+02"')
> > EXTRACT(EPOCH FROM interval '1007 hours');
>
>
>

>From de doc : age(timestamp, timestamp) return an interval so if I
wrote
select age('2009-06-23 18:36:05.064066+02' ,'"2009-05-12 18:36:05.064066
+02"') > interval '1000 hours';

I think I compare an interval with an interval.
the result should be true because there is 1008 hours between the 2
dates
But I need to substract more than 24 hours to get a 'true'

select age('2009-06-23 18:36:05.064066+02' ,'"2009-05-12 18:36:05.064066
+02"') > interval '983 hours';

So age() lost 24 H.