Re: How to GROUP results BY month

From: Mark Roberts <mailing_lists(at)pandapocket(dot)com>
To:
Cc: pgsql-sql(at)postgresql(dot)org
Subject: Re: How to GROUP results BY month
Date: 2008-07-16 16:29:47
Message-ID: 1216225787.26739.225.camel@localhost
Views: Raw Message | Whole Thread | Download mbox | Resend email
Thread:
Lists: pgsql-sql


On Wed, 2008-07-16 at 07:39 +0200, A. Kretschmer wrote:
> am Tue, dem 15.07.2008, um 18:15:07 -0700 mailte Mark Roberts
> folgendes:
> >
> > On Tue, 2008-07-15 at 14:31 +0200, A. Kretschmer wrote:
> > > am Tue, dem 15.07.2008, um 13:12:39 +0100 mailte Oliveiros
> Cristina folgendes:
> > > > Howdy, all,
> > > >
> > > > I have a problem.
> > > >
> > > > I have a table which one of the fields is of type date.
> > > >
> > > > I need to obtain the totals of the other fields in a by-month
> basis
> > > > IS there any easy way to do this using the GROUP BY or any other
> construct?
> > >
> > > ... group by extract(month from date)
> > >
> > >
> > > Andreas
> >
> > It's worth noting that extract(month from timestamp) returns a
> month_no, and thus will not be suitable for grouping queries that span
> years.
>
> Right, but that wasn't the question...

Honestly, the way the question was phrased, I'd have assumed that it
wanted to group by month (not group by a group of months). Jan 08 is
distinct from Jan 07.

Please accept my sincerest apologies if you you feel that I
misinterpreted the question. I was merely trying to illustrate the
difference between what each approach was.

-Mark

In response to

Responses

Browse pgsql-sql by date

  From Date Subject
Next Message Steve Midgley 2008-07-16 17:03:42 Re: Problem with ORDER BY and DISTINCT ON
Previous Message Kaare Rasmussen 2008-07-16 16:10:10 Re: Rollback in Postgres