On Wed, 2007-05-30 at 15:56 -0400, Tom Lane wrote:
> In
> the sync-scan case the idea seems pretty bogus anyway, because the
> actual working set will be N backends' rings not just one.
I don't follow. Ideally, in the sync-scan case, the sets of buffers in
the ring of different scans on the same relation will overlap
completely, right?
We might not be at the ideal, but the sets of buffers in the rings
shouldn't be disjoint, should they?
Regards,
Jeff Davis