From: | Ragnar <gnari(at)hive(dot)is> |
---|---|
To: | Tomi N/A <hefest(at)gmail(dot)com> |
Cc: | pgsql general <pgsql-general(at)postgresql(dot)org> |
Subject: | Re: a question on SQL |
Date: | 2006-12-12 17:13:47 |
Message-ID: | 1165943627.6369.49.camel@localhost.localdomain |
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Lists: | pgsql-general |
On þri, 2006-12-12 at 16:47 +0000, Tomi N/A wrote:
> Don't really know where to ask this...the general mailing list sounds
> like the closest.
>
> Let's say I have three tables: owner, factory and product with a 1:N
> relationship at each step.
> Assuming that a product has a production date, how would you go about
> returning a factory for every owner, where the returned factory is the
> factory that produced the oldest product of it's owner?
> Hints?
someting like this maybe:
select distinct on (owner.id,factory.factoryid) *
from owner,factory,product
where <your join contitions>
order by owner.id,factory.factoryid,production_date
gnari
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