Re: Getting the output of a function used in a where clause

From: Rod Taylor <pg(at)rbt(dot)ca>
To: Bill Lawrence <bill(dot)lawrence(at)cox(dot)net>
Cc: Scott Marlowe <smarlowe(at)g2switchworks(dot)com>, PFC <lists(at)boutiquenumerique(dot)com>, pgsql-sql(at)postgresql(dot)org
Subject: Re: Getting the output of a function used in a where clause
Date: 2005-04-19 02:00:09
Message-ID: 1113876009.41948.1.camel@home
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On Tue, 2005-04-12 at 23:08 -0700, Bill Lawrence wrote:
> Thanks,
>
> Unfortunately, I think that solution requires the distance calculation to be
> executed twice for each record in the table. There are ~70K records in the
> table. Is the postgres query optimizer smart enough to only perform the
> calculation once?

It is in some places, but possibly not in that one.

You can force it with a subselect though:

SELECT * FROM (SELECT zipcode, zipdist($lat1d,$lon1d,lat,long)
as distance
from zipcodes) AS tab where distance <= $dist;

> Bill
>
>
>
> -----Original Message-----
> From: Scott Marlowe [mailto:smarlowe(at)g2switchworks(dot)com]
> Sent: Tuesday, April 12, 2005 6:55 AM
> To: Bill Lawrence
> Cc: PFC; pgsql-sql(at)postgresql(dot)org
> Subject: Re: [SQL] Getting the output of a function used in a where clause
>
> Why not just do:
>
> SELECT zipcode, zipdist($lat1d,$lon1d,lat,long) as distance from
> zipcodes where zipdist($lat1d,$lon1d,lat,long) <= $dist;";
>
>
> On Mon, 2005-04-11 at 20:25, Bill Lawrence wrote:
> > Boy I sure thought that would work... I received the following from
> postgres:
> >
> > ERROR: Attribute "distance" not found.
> >
> > Started looking into gist.... Looks complex.
> >
> > Any other ideas?
> >
> >
> > -----Original Message-----
> > From: PFC [mailto:lists(at)boutiquenumerique(dot)com]
> > Sent: Monday, April 11, 2005 1:51 AM
> > To: Bill Lawrence; pgsql-sql(at)postgresql(dot)org
> > Subject: Re: [SQL] Getting the output of a function used in a where clause
> >
> >
> > try:
> >
> > SELECT zipcode, zipdist($lat1d,$lon1d,lat,long) as distance from zipcodes
> > where distance <= $dist;";
> >
> > OR you could use a gist index with a geometric datatype to get it a lot
> > faster.
> >
> >
> > On Sat, 09 Apr 2005 03:43:39 +0200, Bill Lawrence <bill(dot)lawrence(at)cox(dot)net>
> > wrote:
> >
> > > HI,
> > >
> > > I'm a newbie so please bear with me. I have a function defined (got it
> > > from
> > > one of your threads... thanks Joe Conway) which calculates the distance
> > > between 2 zip code centeroids (in lat,long). This thing works great.
> > > However, I want to sort my results by distance without incurring the
> > > additional burden of executing the function twice. A simplified version
> > > of
> > > my current SQL (written in a perl cgi) that returns a set of zip codes
> > > within a given radius is:
> > >
> > >
> > > What I want to write is something like:
> > >
> > > $sql = "SELECT zipcode, distance from zipcodes where distance <= $dist
> > > order
> > > by distance;";
> > >
> > > But I don't the magic SQL phrase to populate the distance variable using
> > > my
> > > nifty function. Do I need to create an output type for distance?
> > >
> > > Thanks in advance!
> > >
> > > Bill
> > >
> > >
> > >
> >
> >
> >
> >
> > ---------------------------(end of broadcast)---------------------------
> > TIP 7: don't forget to increase your free space map settings
>
>
>
> ---------------------------(end of broadcast)---------------------------
> TIP 4: Don't 'kill -9' the postmaster
>
--

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