| From: | Rod Taylor <rbt(at)rbt(dot)ca> |
|---|---|
| To: | Tom Rochester <tomr(at)chu(dot)com(dot)au> |
| Cc: | pgsql-sql(at)postgresql(dot)org |
| Subject: | Re: substr_count |
| Date: | 2003-07-10 13:43:06 |
| Message-ID: | 1057844586.46100.129.camel@jester |
| Views: | Raw Message | Whole Thread | Download mbox | Resend email |
| Thread: | |
| Lists: | pgsql-sql |
On Thu, 2003-07-10 at 04:38, Tom Rochester wrote:
> Hey all,
>
> I would like to achive something along the lines of:
>
> SELECT field FROM table WHERE field ILIKE '$searchterm' ORDER BY
> substr_count(field, '$searchterm');
>
> Of course the substr_count function does not exist. Is there anyway to
> do this?
>
> I had a thought char_count(replace(field, !$searchterm, '')) might do
> the job but replace doesn't allow for 'replace everything NOT string';
How about:
(char_count(field) - char_count(replace(field, $searchterm, '')))
| From | Date | Subject | |
|---|---|---|---|
| Next Message | Rod Taylor | 2003-07-10 13:47:37 | Re: help yourself by helping others |
| Previous Message | Rod Taylor | 2003-07-10 13:32:00 | Re: Recursive request ... |