I'm having trouble getting an SQL statement to use a variable. Here's
the statement:
$sql = "SELECT emp_fname FROM employee WHERE username = '$username'";
$result = pg_exec($conn,$sql);
if (!$result) {
exit;
}
I get the following warning from this:
Warning: Supplied argument is not a valid PostgreSQL link resource in
/var/www/personnel/include/functions.inc on line 25
Is there another way to use a variable in an SQL statement. This format
works with MySQL.
--
Jeff Self
Information Technology Analyst
Department of Personnel
City of Newport News
2400 Washington Ave.
Newport News, VA 23607
757-926-6930