From: | "Fernando Hevia" <fhevia(at)ip-tel(dot)com(dot)ar> |
---|---|
To: | "'Xavier Bermeo'" <xbermeo(at)gmail(dot)com>, <pgsql-sql(at)postgresql(dot)org> |
Subject: | Re: Cursor |
Date: | 2008-08-19 18:38:00 |
Message-ID: | 022701c9022a$b4e46a00$8f01010a@iptel.com.ar |
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Lists: | pgsql-sql |
> De: pgsql-sql-owner(at)postgresql(dot)org [mailto:pgsql-sql-owner(at)postgresql(dot)org
<mailto:pgsql-sql-owner(at)postgresql(dot)org>] En nombre de Xavier Bermeo
> Enviado el: Sábado, 16 de Agosto de 2008 14:54
> Para: pgsql-sql(at)postgresql(dot)org
> Asunto: [SQL] Cursor
>
> Hi, guys.......
> I have problems with cursosrs.
> Anyone have an example complete the how load and read each position of a
cursor?
> I wait your answer........
> Thanks.......guys
Hi Xavier. This is a very simple example of a function with an implicit
cursor.
Regards,
Fernando.
CREATE OR REPLACE FUNCTION f_cursor()
RETURNS void AS
$BODY$
DECLARE
idx INTEGER;
a mytable.col1%TYPE;
b mytable.col2%TYPE;
c mytable.col3%TYPE;
d mytable.col4%TYPE;
BEGIN
idx :=0;
FOR a, b, c, d IN
SELECT col1, col2, col3, col4
FROM mytable
ORDER BY col1 ;
LOOP
-- Comment: Every iteration in loop will read a row from the cursor
idx := idx + 1;
raise notice 'Row %: [%, %, %, %]', idx, a, b, c, d;
END LOOP;
-- Comment: all rows have been read
END;
$BODY$
LANGUAGE 'plpgsql' VOLATILE;
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