From: | "Fernando Hevia" <fhevia(at)ip-tel(dot)com(dot)ar> |
---|---|
To: | "'Mike Diehl'" <jdiehl(at)sandia(dot)gov>, "'SQL Postgresql List'" <pgsql-sql(at)postgresql(dot)org> |
Subject: | Re: Problem with phone list. |
Date: | 2007-08-15 20:58:22 |
Message-ID: | 021801c7df7f$043d8610$8f01010a@iptel.com.ar |
Views: | Raw Message | Whole Thread | Download mbox | Resend email |
Thread: | |
Lists: | pgsql-sql |
Try this:
Select *
from view v1
where duration = (select max(duration) from view v2 where v2.phone_number =
v1.phone_number)
You could get more than one call listed for the same number if many calls
match max(duration) for that number.
-----Mensaje original-----
De: pgsql-sql-owner(at)postgresql(dot)org [mailto:pgsql-sql-owner(at)postgresql(dot)org]
En nombre de Mike Diehl
Enviado el: Miércoles, 15 de Agosto de 2007 17:28
Para: SQL Postgresql List
Asunto: [SQL] Problem with phone list.
Hi all.
I've qot a problem I need to solve. I'm sure it's pretty simple; I just
can't
seem to get it, so here goes...
I've got a table, actually a view that joins 3 tables, that contains a phone
number, a unique id, and a call duration.
The phone number has duplicates in it but the unique id is unique.
I need to get a list of distinct phone numbers and the coorisponding largest
call duration.
I've got the idea that this should be a self-join on phone number where
a.id<>b.id, but I just can't seem to get the max duration.
Any hints would be much appreciated.
Mike.
---------------------------(end of broadcast)---------------------------
TIP 4: Have you searched our list archives?
From | Date | Subject | |
---|---|---|---|
Next Message | Richard Broersma Jr | 2007-08-15 21:00:05 | Re: Problem with phone list. |
Previous Message | Rodrigo De León | 2007-08-15 20:49:25 | Re: Problem with phone list. |