Re: One to many query question

From: "Chad Thompson" <chad(at)weblinkservices(dot)com>
To: "Dave Dribin" <dave-ml(at)dribin(dot)org>, <pgsql-sql(at)postgresql(dot)org>
Subject: Re: One to many query question
Date: 2003-07-30 21:28:50
Message-ID: 008201c356e1$9245bca0$32021aac@chad
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> On Wed, Jul 30, 2003 at 01:11:35PM -0700, Eric Clark wrote:
> > On Wed, 2003-07-30 at 12:35, Dave Dribin wrote:
> > > CREATE TABLE cd (
> > > id integer unique,
> > > artist varchar(25),
> > > title varchar(25)
> > > );
> > >
> > > CREATE TABLE cd_genres (
> > > cd_id integer,
> > > genre varchar(25)
> > > );
> >
> > I think you've got this backwards. There is no advantage in the above
> > table's over simply having a genre varchar(25) in the cd table.
> >
> > You really want:
> >
> > CREATE TABLE genre (
> > genre_id serial,
> > genre varchar(25)
> > );
> >
> > CREATE TABLE cd (
> > cd_id integer unique,
> > artist varchar(25),
> > title varchar(25),
> > genre_id varchar(25) references genre (genre_id)
> > );
>
> This doesn't allow multiple genre's per CD, though, does it? A CD
> can only have 1 genre_id. I would like the ability to have multiple
> genres, in which case a third table is necessary:
>
> CREATE TABLE cd_genres (
> cd_id integer,
> genre_id integer
> );
>
> cd_id references cd.id and genre_id references genre.genre_id.
>
> This still requires the complex LEFT JOIN query from my first post,
> too, I think, *plus* an extra join between cd_genres and genre.
>
> -Dave

What you may be looking for is a not exists subselect.

Im not sure if this quite fits your example.. but maybe it will give you
some ideas...

SELECT
cd.*,
rock.genre AS rock,
jazz.genre AS jazz,
electronic.genre AS electronic
FROM cd
LEFT JOIN cd_genres jazz ON
(cd.id = jazz.cd_id AND jazz.genre = 'Jazz')
LEFT JOIN cd_genres electronic ON
(cd.id = electronic.cd_id AND electronic.genre = 'Electronic');
WHERE NOT EXISTS
(SELECT cd.id FROM cd join cd_genres rock ON (cd.id = rock.cd_id AND
rock.genre = 'Rock'))

This is quite fast in postgres unless configured wrong.. be sure to join
your subselect to your outer query.

Hope that helps
Chad

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