RE: Select Distinct Order By Array_Position

Wasn’t aware it was possible to put array_position statement in the actual select or is this a select within a select?

Also, I am selecting from an ordered (randomly) subset of data and I need to return the result set in the same order so do have to output the array as part of the order by?

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From: Rob Sargent <robjsargent(at)gmail(dot)com>
Sent: 26 November 2018 19:20
To: Mark Williams <markwillimas(at)gmail(dot)com>
Cc: pgsql-sql(at)lists(dot)postgresql(dot)org
Subject: Re: Select Distinct Order By Array_Position

On Nov 26, 2018, at 12:12 PM, Mark Williams <markwillimas(at)gmail(dot)com <mailto:markwillimas(at)gmail(dot)com> > wrote:

Hi,

I am getting an error “SELECT DISTINCT, ORDER BY expressions must appear in select list”. I am ordering by <http://documents.id/> documents.id and it appears in my select list. So I am guessing the problem lies with the array. Is there any way of achieving this? Query is below.

SELECT DISTINCT <http://documents.id/> documents.id, page_no FROM texts LEFT JOIN documents on <http://documents.id/> documents.id=texts.doc_id WHERE doc_id IN (26194, 2345, 189) AND (text LIKE '%RIVER%') ORDER BY array_position(ARRAY[26194, 2345, 189]::INTEGER[], <http://documents.id/> documents.id)

Thanks,

Mark

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Try put the array_position clause in the select and add documents.id <http://documents.id> to the order by?